-50x^2+1500x+140000=0

Solution for -50x^2+1500x+140000=0 equation:

-50x^2+1500x+140000=0

a = -50; b = 1500; c = +140000;
Δ = b2-4ac
Δ = 15002-4·(-50)·140000
Δ = 30250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30250000}=5500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1500)-5500}{2*-50}=\frac{-7000}{-100}
=+70
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1500)+5500}{2*-50}=\frac{4000}{-100}
=-40
$